UK Oracle User Group

The voting process

The voting process

Below you will find an explanation of the adjudication and voting process for the UKOUG Partner of the Year Awards 2017/18. If you have any further questions, please feel free to contact Lois at


Once nominations have closed, an adjudication panel will review the nominations and shortlist the Partners that will go through to the final customer vote.

The panel will consist of end users, where possible with specialist product knowledge, and excluding anyone who has worked for a company providing Oracle-related products or services in the past 5 years.

Adjudication will take place during July 2017. This selection process will be carried out by awarding points from 1-6 to the top 6 nominees in each category. This will provide a shortlist of a maximum of 6 Partner companies in each voting category, based on the highest scores awarded by the adjudicators.


Once the shortlists for each category have been selected, voting will commence on Monday 24th July 2017 and close 09:00 (BST) Monday 11th September.

Voting is opened to end users of Oracle-related products or services only and voters must use their company email address in order to have a valid vote and can only vote once per category.

This year the voting system has changed. Now voters will just be asked to vote for the company they want to win the category. This is to remove the confusion of voting for 3 companies.

After voting closes, UKOUG will calculate the points and the Partner with the highest score wins.

In each category, a winner will be selected for each level of award (Gold, Silver and Bronze). A Partner can only be awarded one level per category.

At the discretion of UKOUG, categories with fewer than four shortlisted companies may only be awarded a Gold award.

Awards will then be presented on Thursday 12th October 2017 at The Hurlingham Club

We'd love to get your feedback on this; you'll need a UKOUG login to provide it, so if you don't have one, please click on 'create a web profile' first.